document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479752>Question 479752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car cut off the first third of the distance at 80 km / hour. Then cut the second third at 24 km / hour. While the final third made at 48 km / hour. How was the average speed of the car in the entire distance?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328687 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car cut off the first third of the distance at 80 km / hour. Then cut the second third at 24 km / hour. While the final third made at 48 km / hour. How was the average speed of the car in the entire distance??<BR>\n" );
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document.write( "If by \"cut off\" you mean traveled:<BR>\n" );
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document.write( "Total time = d/80 + d/24 + d/48 were d is 1/3 of the total distance<BR>\n" );
document.write( "tt = 3d/40 = total distance/40<BR>\n" );
document.write( "Avg speed = 40 km/hr\r<BR>\n" );
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document.write( " </SPAN>\n" );
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