document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479610>Question 479610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help solve the system of equations<BR>\n" );
document.write( "y=50+0.15(x-500) and y=105+0.10(x-650)\r<BR>\n" );
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document.write( "Solve the system of linear equations algebraically using either the substitution method or the elimination method to determine where the two cost options are equivalent, showing all work.\r<BR>\n" );
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document.write( "a. Explain each step used to solve the system of linear equations. Include the following in your explanation:<BR>\n" );
document.write( "• The algebraic method used to solve the system of equations<BR>\n" );
document.write( "• All mathematical operations used to solve the system of equations<BR>\n" );
document.write( "• The solution of the system of equations<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328607 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=50+0.15(x-500)<BR>\n" );
document.write( "y= 50+0.15x-75<BR>\n" );
document.write( "y-0.15x=-25 ........1\r<BR>\n" );
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document.write( "y=105+0.10(x-650)<BR>\n" );
document.write( "y= 105 +0.10x-65<BR>\n" );
document.write( "y-0.10x=40............2\r<BR>\n" );
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document.write( "Use the elimination method to find x & y\r<BR>\n" );
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document.write( "-0.15	x	+	1	y	=	-25	.............1	<BR>\n" );
document.write( "-0.1	x	+	1	y	=	40	.............2	<BR>\n" );
document.write( "Eliminate y								<BR>\n" );
document.write( "multiply (1)by 		-1						<BR>\n" );
document.write( "Multiply (2) by		1						<BR>\n" );
document.write( "0.15	x		-1	y	=	25		<BR>\n" );
document.write( "-0.1	x	+	1	y	=	40		<BR>\n" );
document.write( "Add the two equations								<BR>\n" );
document.write( "0.05	x				=	65		<BR>\n" );
document.write( "/	0.05							<BR>\n" );
document.write( "x	=	1300    			<BR>\n" );
document.write( "plug value of 			x	in (1)				<BR>\n" );
document.write( "-0.15	x	+	1	y	=	-25		<BR>\n" );
document.write( "-195		+	1	y	=	-25		<BR>\n" );
document.write( "			1	y	=	-25	+	195<BR>\n" );
document.write( "			1	y	=	170		<BR>\n" );
document.write( "				y	=	170\r<BR>\n" );
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document.write( "The solution of system of equations (1300,170)<BR>\n" );
document.write( "m.ananth@hotmail.ca\r<BR>\n" );
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