document.write( "Question 479546: A ball is thrown vertically upward at a velocity of 15 feet per second from a bridge that is 55 feet above the level of the water. The height h, in feet, of the ball above the water at the time t in seconds after it is thrown is
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document.write( "h = 16t^2 + 20t - 48
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document.write( "Find the time when the ball strikes the water \n" );
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Algebra.Com's Answer #328597 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! h = 16t^2 + 20t - 48 \n" ); document.write( "--------------------- \n" ); document.write( "If the initial upward speed is 15 ft/sec and the bridge is 55 ft above the water, the eqn would be \n" ); document.write( "h(t) = -16t^2 + 15t + 55 \n" ); document.write( "------------------------- \n" ); document.write( "The equation you gave shows increasing altitude with time. It starts at -48 feet and never comes down. \n" ); document.write( " \n" ); document.write( " |