document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467155>Question 467155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: Line AB is parallel to Line CD; Ray BF bisects Angle ABE; Ray DG bisects Angle CDB <BR>\n" );
document.write( "PROVE: Line BF is parallel to Line DG </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328587 by </B><A HREF=/tutors/aboutme.mpl?userid=Aswathy><B>Aswathy(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aswathy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As, AB is parallel to CD.Then by corresponding angles axiom,<BR>\n" );
document.write( "ABE=CDB<BR>\n" );
document.write( "as,FB & GD are angle bisectors<BR>\n" );
document.write( "So,1/2ABE=1/2CDB<BR>\n" );
document.write( "So,FBE=GDB<BR>\n" );
document.write( "Now by converse of corresponding angles axiom,<BR>\n" );
document.write( "BF is parallel to GD </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );