document.write( "Question 479519: Respected Sir/Madam ,
\n" ); document.write( "Please help me to solve my problem . I Will be very grateful for your help. My question is :
\n" ); document.write( "If (log a)/(y-z) =(log b)/ (z-x)=(log c) / (x-y) then what is the value of a^(y+z) * b ^ (z+x) *c^(x+y)
\n" ); document.write( "As the Answer given is :1
\n" ); document.write( "So please Sir/Madam provide me the steps for this question..\r
\n" ); document.write( "\n" ); document.write( "Thank you,
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Algebra.Com's Answer #328585 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
1. \"+%28log+a%29%2F%28y-z%29+=%28log+b%29%2F+%28z-x%29=%28log+c%29+%2F+%28x-y%29\" or
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\n" ); document.write( "Use formula \"n%2Aloga=log%28a%5En%29\"
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\n" ); document.write( "\"+a%5E%281%2F%28y-z%29%29+=+b%5E%281%2F+%28z-x%29%29=c%5E%281+%2F+%28x-y%29%29\"
\n" ); document.write( "So \"+a%5E%281%2F%28y-z%29%29+=+b%5E%281%2F+%28z-x%29%29\" then \"%28+a%5E%281%2F%28y-z%29%29%29%5E%28z-x%29+=+%28b%5E%281%2F+%28z-x%29%29%29%5E%28z-x%29\" => \"b=a%5E%28%28z-x%29%2F%28y-z%29%29\"
\n" ); document.write( "\"+a%5E%281%2F%28y-z%29%29=c%5E%281+%2F+%28x-y%29%29\", then \"+%28a%5E%281%2F%28y-z%29%29%29%5E%28x-y%29+=%28c%5E%281+%2F+%28x-y%29%29%29%5E%28x-y%29\" => \"c=a%5E%28%28x-y%29%2F%28y-z%29%29\"
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\n" ); document.write( "2.
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