document.write( "Question 49477: Solve. (x + 3)2 = 6 \n" ); document.write( "
Algebra.Com's Answer #32853 by Osran_Shri(18)![]() ![]() ![]() You can put this solution on YOUR website! (x + 3)2 = 6\r \n" ); document.write( "\n" ); document.write( "if it is a simple equation then:\r \n" ); document.write( "\n" ); document.write( "2x + 6 =6 \n" ); document.write( "2x = 12 \n" ); document.write( "x = 6\r \n" ); document.write( "\n" ); document.write( "If it is a quadratic equation then, follw the solution as below:\r \n" ); document.write( "\n" ); document.write( "(x+3)^2 = 6\r \n" ); document.write( "\n" ); document.write( "x^2 + 3^2 + 2*x*3 = 6\r \n" ); document.write( "\n" ); document.write( "x^2 + 6x = 6 - 6\r \n" ); document.write( "\n" ); document.write( "x^2 + 6x = 0\r \n" ); document.write( "\n" ); document.write( "This quadratic equation can be factored to solve for \"x\" \n" ); document.write( "Use the principle of zero products,which says, if ab = 0, either a, b, or both must be equal to zero.\r \n" ); document.write( "\n" ); document.write( "x ( x + 6 ) = 0\r \n" ); document.write( "\n" ); document.write( "As per above principle,\r \n" ); document.write( "\n" ); document.write( "x = 0 and x+6 = 0 ------> x = -6\r \n" ); document.write( "\n" ); document.write( "Therefore x = 0, -6\r \n" ); document.write( "\n" ); document.write( "B.Shridhar \n" ); document.write( " \n" ); document.write( " |