document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479455>Question 479455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x: 3^1-2x= e^0.5x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328497 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x: <BR>\n" );
document.write( "3^(1-2x) = e^0.5x<BR>\n" );
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document.write( "Take the natural log of both sides:<BR>\n" );
document.write( "(1-2x)ln(3) = 0.5x<BR>\n" );
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document.write( "ln(3) - 2xln(3) = 0.5x<BR>\n" );
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document.write( "x[2ln(3)+0.5] = ln(3)<BR>\n" );
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document.write( "x[ln(9)+0.5] = ln(3)<BR>\n" );
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document.write( "x = ln(3)/[ln(9)+0.5]<BR>\n" );
document.write( "x = 0.4073<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==============<BR>\n" );
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