document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479279>Question 479279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this.<BR>\n" );
document.write( "3x + y = 26<BR>\n" );
document.write( "-6x + y = -37<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328433 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + y = 26<BR>\n" );
document.write( "-6x + y = -37 --> y = 6x-37<BR>\n" );
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document.write( "Sub for y in the 1st equation and find x.<BR>\n" );
document.write( "Then use either eqn to find y.\r<BR>\n" );
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