document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479142>Question 479142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of an isosceles right triangle is 10sqrt of 2.find the lengths of the other sides?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328314 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If it is an isosceles right-angled triangle then the square on the hypotenuse equals twice the square of the other sides (which is the sum of the squares of the other two sides because they are equal).\r<BR>\n" );
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document.write( "(10 sqrt of 2) squared = 200 = twice the other sides squared.\r<BR>\n" );
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document.write( "Therefore the other sides squared = 100; giving the other sides are 10.\r<BR>\n" );
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document.write( "10 squared plus 10 squared  = 200 =  (10 sqrt 2) squared. </SPAN>\n" );
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