document.write( "Question 479127: solve by the substitution method.\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2=13
\n" ); document.write( "2x-3y=0
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Algebra.Com's Answer #328307 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
\"system%28x%5E2%2By%5E2=13%2C2x-3y=0%29\"
\n" ); document.write( "from the second equation \"-3y=-2x\", or \"y=2x%2F3\"
\n" ); document.write( "Substitute \"y=2x%2F3\" into the first equation
\n" ); document.write( "\"x%5E2%2B%282x%2F3%29%5E2=13\"
\n" ); document.write( "\"x%5E2%2B4x%5E2%2F9=13\"
\n" ); document.write( "\"13x%5E2%2F9=13\" multiply by 9
\n" ); document.write( "\"13x%5E2=117\" divide by 13
\n" ); document.write( "\"x%5E2=9\"
\n" ); document.write( "\"x%5B1%5D=3\", \"x%5B2%5D=-3\"
\n" ); document.write( "substitute into \"y=2x%2F3\"
\n" ); document.write( "\"y%5B1%5D=2%2A3%2F3=2\", \"y%5B2%5D=2%2A%28-3%29%2F3=-2\"
\n" ); document.write( "Answer (3,2) and (-3,-2)\r
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