document.write( "Question 479110: the perimeter of a triangle is 71cm. the first side is 3cm shorter than the second side, and the third side is twice as long as the first side. find the length of the longest side \n" ); document.write( "

Algebra.Com's Answer #328294 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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Let x is the first side
\n" ); document.write( "Then the second side is $\"%28x%2B3%29\"$ cm, the third side is $\"2x\"$ cm, so the perimeter is $\"x%2B%28x%2B3%29%2B2x=71\"$
\n" ); document.write( " $\"x%2Bx%2B3%2B2x=71\"$
\n" ); document.write( " $\"4x=71-3\"$
\n" ); document.write( " $\"4x=68\"$
\n" ); document.write( " $\"x=68%2F4\"$
\n" ); document.write( " $\"x=17\"$
\n" ); document.write( "The first side is $\"17\"$ cm, the second side is $\"%2817%2B3%29=20\"$ cm, the third is $\"2%2A17=34\"$ cm
\n" ); document.write( "The length of the longest side is $\"34\"$ cm \n" ); document.write( "

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