document.write( "Question 479098: A father is 36 years older than his son. In 9 years, he will be 1/3 of his father's age. How old are they? \n" ); document.write( "
Algebra.Com's Answer #328293 by Maths68(1474)\"\" \"About 
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Father’s age = F
\n" ); document.write( "Son’s age = S
\n" ); document.write( "Father is 36 years older. If we add 36 to the son’s age both will be the same age.
\n" ); document.write( "F=S+36 …………(1)
\n" ); document.write( "In 9 years means add 9 to both ages
\n" ); document.write( "F+9=S+9
\n" ); document.write( "Son will be 1/3 of his father’s age
\n" ); document.write( "(F+9)/3=S+9
\n" ); document.write( "F+9=3(S+9)
\n" ); document.write( "F+9=3S+27
\n" ); document.write( "F=3S+27-9
\n" ); document.write( "F=3S+18
\n" ); document.write( "Put the value of F from equation (1)
\n" ); document.write( "S+36=3S+18
\n" ); document.write( "36-18=3S-S
\n" ); document.write( "18=2S
\n" ); document.write( "18/2=S
\n" ); document.write( "S=9
\n" ); document.write( "Put the value of S in equation (1)
\n" ); document.write( "F=S+36
\n" ); document.write( "F=9+36
\n" ); document.write( "F=45\r
\n" ); document.write( "\n" ); document.write( "So Father is 45 years old and Son is 9 years old.
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