document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=479056>Question 479056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on how to do this problem.... If x= 6 and y= 4, then xy-3x=?  plzz help mii step by step </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328266 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If x= 6 and y= 4, then xy-3x=?<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Sub 6 for x and 4 for y<BR>\n" );
document.write( "xy - 3x = 6*4 - 3*6<BR>\n" );
document.write( "= 24 - 18<BR>\n" );
document.write( "= 6<BR>\n" );
document.write( " </SPAN>\n" );
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