document.write( "Question 479051: log4 4^0.8=x
\n" ); document.write( "b^x=y
\n" ); document.write( "4^x=4^0.8
\n" ); document.write( "x=√4^0.8
\n" ); document.write( "x=1.74
\n" ); document.write( "but when changing 4^1.74=11.16 and 4^.8=3.03 I can't seem to be doing this right since the exponents do not match the value. please help
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Algebra.Com's Answer #328264 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
log4 4^0.8=x
\n" ); document.write( "b^x=y
\n" ); document.write( "4^x=4^0.8
\n" ); document.write( "----------
\n" ); document.write( "If you mean \"log%284%2C4%5E0.8%29+=+x\"
\n" ); document.write( "then x = 0.8
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