document.write( "Question 479066: how to solve equation
\n" ); document.write( "3y+20=3+2y\r
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\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #328261 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
3y + 20 = 3 + 2y
\n" ); document.write( "Subtract 2y from both sides.
\n" ); document.write( "y + 20 = 3
\n" ); document.write( "Subtract 20 from both sides.
\n" ); document.write( "y = -17
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\n" ); document.write( "Check your work!
\n" ); document.write( "3y+20 = -51+20 = -31
\n" ); document.write( "3 + 2y = 3 +(-34) = -31
\n" ); document.write( "True
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\n" ); document.write( "Done
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