document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478986>Question 478986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many litres of a 30% acid solution should be added to 20 litres of a 60% acid solution in order to obtain a 50% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328238 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -------	percent	----------------	quantity										<BR>\n" );
document.write( "Alcohol I	60	----------------			20	ounces							<BR>\n" );
document.write( "Alcohol II	30	----------------			x	ounces							<BR>\n" );
document.write( "Total	50	----------------	20	+	x	ounces							<BR>\n" );
document.write( "													<BR>\n" );
document.write( "60*20+30	*x=50(20	+x	)<BR>\n" );
document.write( "													<BR>\n" );
document.write( "1200+30	x=1000+50x					<BR>\n" );
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document.write( "30	x	-	50	x	=	1000	-	1200					<BR>\n" );
document.write( "													<BR>\n" );
document.write( "-20	x	=	-200						/		-20							<BR>\n" );
document.write( "x	=		10	ounces	30	%	Alcohol II						<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );