document.write( "Question 478776: Find the 3 consecutive multiples of 5 so that the square of the third decreased by 5 times the second number is the same as 25 more than twice the product of the first two numbers. \n" ); document.write( "
Algebra.Com's Answer #328216 by ankor@dixie-net.com(22740)\"\" \"About 
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Find the 3 consecutive multiples of 5
\n" ); document.write( "x, (x+5), (x+10)
\n" ); document.write( ":
\n" ); document.write( "\"the square of the third decreased by 5 times the second number is the same as 25 more than twice the product of the first two numbers.\"
\n" ); document.write( "(x+10)^2 - 5(x+5) = 2x(x+5) + 25
\n" ); document.write( "x^2 + 20x + 100 - 5x - 25 = 2x^2 + 10x + 25
\n" ); document.write( "combine like terms
\n" ); document.write( "x^2 + 15x + 75 = 2x^2 + 10x + 25
\n" ); document.write( "Combine on the right
\n" ); document.write( "0 = 2x^2 - x^2 + 10x - 15x + 25 - 75
\n" ); document.write( "0 = x^2 - 5x - 50
\n" ); document.write( "Factors to
\n" ); document.write( "(x-10)(x+5) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "x = 10, 15, 20 are the three numbers
\n" ); document.write( "and
\n" ); document.write( "x = -5, 0, 5 can be the three numbers also
\n" ); document.write( ":
\n" ); document.write( "You can check both of these in the original statemet \n" ); document.write( "
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