document.write( "Question 478960: How much pure alcohol must be added to 10 gallons of 35% alcohol to have a solution that is 60% alcohol? Solve by substitution method \n" ); document.write( "
Algebra.Com's Answer #328187 by Earlsdon(6294)\"\" \"About 
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Let x = the number of gallons of pure alcohol to be added to the 10 gallons of 35% alcohol solution to obtain (10+x) gallons of 60% alcohol solution.
\n" ); document.write( "You can write the equation for the amount of alcohol as follows (after changing the percentages to their decimal equivalents):
\n" ); document.write( "\"0.35%2810%29%2Bx+=+%280.6%29%2810%2Bx%29\" Simplify and solve for x.
\n" ); document.write( "\"0.35%2810%29%2Bx+=+6%2B0.6x\"
\n" ); document.write( "\"3.5%2Bx+=+6%2B0.6x\" Subtract 0.6x from both sides.
\n" ); document.write( "\"3.5%2B0.4x+=+6\" Subtract 3.5 from both sides.
\n" ); document.write( "\"0.4x+=+2.5\" Finally, didvide oth sides by 4.
\n" ); document.write( "\"x+=+6.25\"gallons of pure alcohol.
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