document.write( "Question 478947: Please,please, help me I am having a horrible time with this class.\r
\n" ); document.write( "\n" ); document.write( "angle PQR, and angle ABC are supplementary, and angle PQR is three times as large as angle ABC. Determine the measure of each angle, show work step by step.
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Algebra.Com's Answer #328168 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "angle \"PQR\", and angle \"ABC\" are \"supplementary\", ...Supplementary angles are pairs of angles that add up to \"180+\"\r
\n" ); document.write( "\n" ); document.write( "so, \"PQR+%2B+ABC=180\".........1\r
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\n" ); document.write( "\n" ); document.write( "and angle \"PQR\" is three times as large as angle \"ABC\":\r
\n" ); document.write( "\n" ); document.write( " \"PQR=3ABC\"....2...substitute in 1\r
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\n" ); document.write( "\n" ); document.write( "Determine the measure of each angle:\r
\n" ); document.write( "\n" ); document.write( "\"PQR=3ABC\"....2...substitute in 1\r
\n" ); document.write( "\n" ); document.write( "\"3ABC+%2B+ABC=180\".........1\r
\n" ); document.write( "\n" ); document.write( "\"4ABC=180\"\r
\n" ); document.write( "\n" ); document.write( "\"ABC=180%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"ABC=45\"....now find \"PQR\"\r
\n" ); document.write( "\n" ); document.write( "\"PQR=3ABC\"....2\r
\n" ); document.write( "\n" ); document.write( "\"PQR=3%2A45\"\r
\n" ); document.write( "\n" ); document.write( "\"PQR=135\"\r
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