document.write( "Question 49429This question is from textbook
\n" ); document.write( ": five times the smallest of three consecutive odd integers is ten more than twice the largest. find the integers. \n" ); document.write( "

Algebra.Com's Answer #32816 by Nate(3500) $\"\"$ $\"About$

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first integer = i
\n" ); document.write( "second integer = i + 2
\n" ); document.write( "third integer = i + 4
\n" ); document.write( " $\"5i+=+2%28i+%2B+4%29+%2B+10\"$
\n" ); document.write( " $\"5i+=+2i+%2B+8+%2B+10\"$
\n" ); document.write( " $\"3i+=+18\"$
\n" ); document.write( " $\"i+=+6\"$
\n" ); document.write( "first integer = i = 6
\n" ); document.write( "second integer = i + 2 = 8
\n" ); document.write( "third integer = i + 4 = 10
\n" ); document.write( "Since these are positive, no such integers exists. \n" ); document.write( "

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