document.write( "Question 478883: The perimeter of a rectangle is 210 inches. The length exceeds the width by 41 inches. What is the length and width? \n" ); document.write( "

Algebra.Com's Answer #328125 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "The length exceeds the width by 41 inches. 
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document.write( "Let x and (x+41in) represent the width and length respectively
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document.write( "Question states***
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document.write( "  2(x+41in) + 2x = 210in
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document.write( "     4x = 128in
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document.write( "      x = 32in, the width.  the length is 73in.  (32in + 41in)\r
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document.write( "CHECKING our Answer***
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document.write( "    2*32in + 2*73in = 64in + 146in = 210in \n" );
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