document.write( "Question 49410: Solve by using the quadratic formula. 5x2 + 3x = 7 \n" ); document.write( "

Algebra.Com's Answer #32812 by Earlsdon(6294) $\"\"$ $\"About$

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Solve $\"5x%5E2%2B3x+=+7\"$ by using the quadratic formula: $\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"$ \r
\n" ); document.write( "\n" ); document.write( "Start by putting your equation in \"standard form\": $\"ax%5E2%2Bbx%2Bc+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"5x%5E2%2B3x-7+=+0\"$ Compare with the standard form: a = 5, b = 3, and c = -7 Substitute these into the quadratic formula and solve for x.\r
\n" ); document.write( "\n" ); document.write( " $\"x+=+%28-3%2B-sqrt%283%5E2-4%285%29%28-7%29%29%29%2F2%285%29\"$ Simplify.
\n" ); document.write( " $\"x+=+%28-3%2B-sqrt%289%2B140%29%29%2F10\"$
\n" ); document.write( " $\"x+=+%28-3%2B-sqrt%28149%29%29%2F10\"$ \r
\n" ); document.write( "\n" ); document.write( "Roots are:
\n" ); document.write( " $\"x+=+-3%2F10%2B%28sqrt%28149%29%29%2F10\"$
\n" ); document.write( " $\"x+=+-3%2F10-%28sqrt%28149%29%29%2F10\"$
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