document.write( "Question 478795: I am stuck on this question!!
\n" ); document.write( "Sam has some quarters, nickels, and dimes. He has 4 more
\n" ); document.write( "quarters than dimes and 3 more dimes than nickels. If n
\n" ); document.write( "represents the number of nickels he has, which of the
\n" ); document.write( "following represents, in cents, the total value of all his
\n" ); document.write( "coins?
\n" ); document.write( "A. 40n + 205
\n" ); document.write( "B. 40n + 130
\n" ); document.write( "C. 40n + 7
\n" ); document.write( "D. 7n + 130
\n" ); document.write( "E. 3n + 10
\n" ); document.write( "

Algebra.Com's Answer #328052 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i get 40n + 205
\n" ); document.write( "we can test to see if this is accurate.
\n" ); document.write( "first we'll solve.
\n" ); document.write( "n = number of nickels.
\n" ); document.write( "d = number of dimes
\n" ); document.write( "q = number of quarters
\n" ); document.write( "he has 4 more quarters than dimes.
\n" ); document.write( "this leads to the equation:
\n" ); document.write( "q = d + 4
\n" ); document.write( "he has 3 more dimes than nickels
\n" ); document.write( "this leads to the equation:
\n" ); document.write( "d = n + 3
\n" ); document.write( "since d = n + 3 and q = d + 4, this means that:
\n" ); document.write( "q = (n+3)+4 which leads to:
\n" ); document.write( "q = n+7
\n" ); document.write( "so we have:
\n" ); document.write( "d = n + 3
\n" ); document.write( "q = n + 7
\n" ); document.write( "now we need to get to the value equation.
\n" ); document.write( "a quarter is worth 25 cents, so we multiply the number of quarters by 25 to get their value in cents.
\n" ); document.write( "a dime is worth 10 cents, so we multiply the number of dimes by 10 to get their value in cents.
\n" ); document.write( "a nickel is worth 5 cents, so we multiply the number of nickels by 5 to get their value in cents.
\n" ); document.write( "the total value of our money is:
\n" ); document.write( "25q + 10d + 5n
\n" ); document.write( "since q is equal to n+7 and d is equal to n+3, we can replace q and d in this equation to get:
\n" ); document.write( "25(n+7) + 10(n+3) + 5n
\n" ); document.write( "simplify this to get:
\n" ); document.write( "25n + 175 + 10n + 30 + 5n
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "40n + 205
\n" ); document.write( "that's the value of our money.
\n" ); document.write( "now let's see if this equation makes sense.
\n" ); document.write( "suppose we have 100 nickels.
\n" ); document.write( "the total value of our money should be:
\n" ); document.write( "40*100 + 205 = 4205 cents
\n" ); document.write( "we are saying that 25q + 10d + 5n = 4205
\n" ); document.write( "n = 100
\n" ); document.write( "d = n+3 = 103
\n" ); document.write( "q = d+4 = 107
\n" ); document.write( "25(107) + 10(103) + 5(100) should be equal to 4205 if everything is copacetic.
\n" ); document.write( "multiplying these out gets us:
\n" ); document.write( "2675 + 1030 + 500 = 4205
\n" ); document.write( "the value of the money equals the same whether we used the initial equation or the final equation so we're good.
\n" ); document.write( "your answer is:
\n" ); document.write( "40n + 205 (selection A)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );