document.write( "Question 478723: (8.62) In 1992, the FAA conducted 20,000 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1000 were positive. \r
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document.write( "(a) Construct a 95 percent confidence interval for the population proportion of positive drug tests. \r
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document.write( "(b) May you assume that this is a normal distribution? Explain why. (Check the normality of your proportion!)
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Algebra.Com's Answer #328039 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In 1992, the FAA conducted 20,000 pre-employment drug tests on job applicants who were to be engaged in safety and security-related jobs, and found that 1000 were positive. \n" ); document.write( "(a) Construct a 95 percent confidence interval for the population proportion \n" ); document.write( "--- \n" ); document.write( "p-hat = 1/20 = 0.05 \n" ); document.write( "--- \n" ); document.write( "ME = 1.96*sqrt[0.05*0.95/20,000) = 0.003 \n" ); document.write( "---- \n" ); document.write( "95%CI: 0.05-0.003 < p < 0.05+0.003 \n" ); document.write( "--- \n" ); document.write( "0.047 < p < 0.053 \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |