document.write( "Question 478282: a square poster has sides measuring 2 feet less than the sides of a square sign. if the difference between their areas is 32 square feet, find the lengths of the sides of the poster and the sign \n" ); document.write( "
Algebra.Com's Answer #328023 by cleomenius(959)![]() ![]() You can put this solution on YOUR website! The area of the sign minus the area of the poster is given as 32 sq ft. \n" ); document.write( "The equation will be: \n" ); document.write( "(x + 2)^2 - x^2 = 32 \n" ); document.write( "x^2 + 4x + 4 - x^2 = 32 \n" ); document.write( "4x + 4 = 32 \n" ); document.write( "4x = 28 \n" ); document.write( "x = 7 ft, the side of the poster. \n" ); document.write( "x + 2 = 9 ft, the size of the sign \n" ); document.write( "Too check: \n" ); document.write( "81 sq ft minus 49 sq ft = 32 sq ft. \n" ); document.write( "Cleomenius. \n" ); document.write( " |