document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=314818>Question 314818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #328003 by </B><A HREF=/tutors/aboutme.mpl?userid=karthiktcs><B>karthiktcs(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=karthiktcs><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=328003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the present age of son be x<BR>\n" );
document.write( "and the present age of father be 3x\r<BR>\n" );
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document.write( "after fifteen years<BR>\n" );
document.write( "(3x+15)=2(x+15)\r<BR>\n" );
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document.write( "(3x+15)=(2x+30)<BR>\n" );
document.write( "3x+15-2x-30=0<BR>\n" );
document.write( "x-15=0<BR>\n" );
document.write( "x=15\r<BR>\n" );
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document.write( "father age will be 3*15=45<BR>\n" );
document.write( " </SPAN>\n" );
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