document.write( "Question 478711: Hi,\r
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document.write( "I tried to solve 5^logx=50-x^log5 in the following manner
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document.write( "Re- aligning the equation
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document.write( "5^logx+x^log5 =50
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document.write( "Taking log both sides
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document.write( "logx X log5 + logx X log5=log50
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document.write( "log(x+5) + log(x+5)=log50
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document.write( "From here am having confusion
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document.write( "1.
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document.write( "log(x+5)(x+5)=log50
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document.write( "log(x+5)^2=log50
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document.write( "(x+5)^2=50=>x=(50)^1/2-(5) (or)
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document.write( "2.
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document.write( "log(x+5) + log(x+5)=log50
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document.write( "2log(x+5)=log50
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document.write( "2(x+5)=50
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document.write( "x+5=25
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document.write( "x=20\r
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document.write( "Which is correct?\r
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document.write( "Thanks and regards,
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document.write( "AN \n" );
document.write( "
Algebra.Com's Answer #327998 by Tatiana_Stebko(1539)![]() ![]() You can put this solution on YOUR website! I am sorry, but all incorrect \n" ); document.write( "Your error - you incorrect use formula \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "So \n" ); document.write( "Substitute in equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |