document.write( "Question 478499: -in high school graduating class of 100 students, 54 studies mathematics.69studies history,35 studies both math and history . if one of these students is selected randomly.find the probability that
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document.write( "a.the students took math or history.
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document.write( "b.the students did'nt take either of these subjects.
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document.write( "c.the students took history but not math.
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Algebra.Com's Answer #327993 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! P(Studies Maths)=P(M)=54/100=0.54 \n" ); document.write( "P(Studies History)=P(H)=69/100=0.69 \n" ); document.write( "P(Studies Maths and History)=P(M∩H)=35/100=0.35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a) the students took math or history.\r \n" ); document.write( "\n" ); document.write( "P(M U H)=? \n" ); document.write( "P(MUH)=P(M)+P(H)-P(M∩H) \n" ); document.write( "P(MUH)=(0.54+0.69)-0.35 \n" ); document.write( "P(MUH)=(0.54+0.69)-0.35 \n" ); document.write( "P(MUH)=1.23-0.35 \n" ); document.write( "P(MUH)=0.88\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) the students did'nt take either of these subjects.\r \n" ); document.write( "\n" ); document.write( " P(Not MUH)=1-P(MUH)=1-0.88=0.12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c) the students took history but not math.\r \n" ); document.write( "\n" ); document.write( "The students took History but not Maths = Students took History – Students took both History and Maths \n" ); document.write( "=69-35 \n" ); document.write( "=34 \n" ); document.write( "P(History not Maths)=34/100 \n" ); document.write( "P(History not Maths)=0.34 \n" ); document.write( " |