document.write( "Question 478665: In 1960, the life expectancy in the UK was 71.1 years. In 2008, it was 79.9 years. Let F(t) = life expectancy and t = the number of years since 1960.
\n" ); document.write( "a) Find a linear function that fits the data.
\n" ); document.write( "b) Use the function of Part (a) to estimate the life expectancy in 2010.
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Algebra.Com's Answer #327971 by mananth(16946)\"\" \"About 
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year life expectancy
\n" ); document.write( "1960 71.1 years
\n" ); document.write( "2008 79.9 years
\n" ); document.write( "Difference
\n" ); document.write( "48 8.8
\n" ); document.write( "Increase in life expectancy per year = 8.8 / 48 = 0.18
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\n" ); document.write( "F(t)= 71.1 + 0.18 t
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\n" ); document.write( "2010 t= 50
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\n" ); document.write( "F(t)= 71.1 + 0.18 * 50
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\n" ); document.write( "F ( 2010 )= 80.27 years
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