document.write( "Question 49364This question is from textbook
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document.write( ": I am doing something wrong here if you could please assist... sqrt 4x + 8, + 8=0
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document.write( "I dropped the zero, and minused (-8)^2 and I came up with 4. \n" );
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Algebra.Com's Answer #32797 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! I am only guessing that the comma is an 'x': \n" ); document.write( "sqrt(4x) + 8x + 8 = 0 \n" ); document.write( "sqrt(4x) = -8x - 8 \n" ); document.write( "4x = (-8x - 8)^2 \n" ); document.write( "4x = 64x^2 + 128x + 64 \n" ); document.write( "0 = 64x^2 + 124x + 64 \n" ); document.write( "0 = 16x^2 + 31x + 16 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "or do you mean: \n" ); document.write( "sqrt(4x + 8) + 8 = 0 \n" ); document.write( "sqrt(4x + 8) = -8 \n" ); document.write( "4x + 8 = 64 \n" ); document.write( "4x = 56 \n" ); document.write( "x = 14 \n" ); document.write( "If you plug fourteen in, you get 16 = 0. That is not true, so the answer is no solution. \n" ); document.write( " |