document.write( "Question 478660: An amount of 40% acid solution is to be mixed with enough 10% acid solution to make 25% acid solution. If there are to be 20 litres of the final mixture, how much of each solution should be mixed together? \n" ); document.write( "
Algebra.Com's Answer #327967 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
percent percentage ---------------- quantity
\n" ); document.write( "Salt solution 10 ---------------- x liters
\n" ); document.write( "Salt solution 40 ---------------- 20 - x liters
\n" ); document.write( "Mixture 25.00% ---------------- 20
\n" ); document.write( "
\n" ); document.write( "10 x + 40 ( 20 - x ) = 25 * 20
\n" ); document.write( "
\n" ); document.write( "10x+800- 40x=500
\n" ); document.write( "10x-40x= 500-800
\n" ); document.write( "-30x=-300
\n" ); document.write( "/-30
\n" ); document.write( "x=10 liters 10.00% Salt solution
\n" ); document.write( "10 liters 40.00% Salt solution
\n" ); document.write( "
\n" ); document.write( "
\n" );