document.write( "Question 478615: log4x+log4(x-6)=2 \n" ); document.write( "
Algebra.Com's Answer #327925 by lwsshak3(11628)\"\" \"About 
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log4x+log4(x-6)=2
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\n" ); document.write( "log4x+log4(x-6)=2
\n" ); document.write( "place under single log using multiplication rule
\n" ); document.write( "log4(x(x-6))=2
\n" ); document.write( "convert to exponential form:(base(4) raised to log of number(2)=number(x(x-6)
\n" ); document.write( "4^2=x(x-6)
\n" ); document.write( "16=x^2-6x
\n" ); document.write( "x^2-6x-16=0
\n" ); document.write( "(x-8)(x+2)=0
\n" ); document.write( "x=8
\n" ); document.write( "or
\n" ); document.write( "x=-2 (reject, x>0) \n" ); document.write( "
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