document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478568>Question 478568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> NEED HELP SIMPLIFYING <BR>\n" );
document.write( "4(SQUARE ROOT OF 3)-2(SQUARE ROOT OF 14)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327898 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe this has been simplified as far as it can go.<BR>\n" );
document.write( "4*sqrt(3) - 2*sqrt(14) appears to be it.<BR>\n" );
document.write( "14 can't be factored by anything except 2 and 7, neither of which is a perfect square so neither can be brought out from underneath the square root sign.<BR>\n" );
document.write( "example of a perfect square would be sqrt(32)<BR>\n" );
document.write( "this can be factored to sqrt(2*16)<BR>\n" );
document.write( "16 is a perfect square so it can be brought out from under the square root to get 4*sqrt(2)<BR>\n" );
document.write( "about the only thing you can do with this one is factor out a 2 to get:<BR>\n" );
document.write( "4*sqrt(3) - 2*sqrt(14) = 2*(2sqrt(3) - sqrt(14))<BR>\n" );
document.write( "other than that, i don't see anything else you can do with thiss.<BR>\n" );
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