document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478578>Question 478578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, my name is Brandon Jones. I'm in the 12th grade and I'm taking AP Calculus. School just started for me on Thursday, 08/04/11 and I am a little rusty. I am having trouble with solving for indicated variables. Here's one of the problems and what I have so far:\r<BR>\n" );
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document.write( "V=2(ab+bc+ac); a (looking for a)....this is what I got so far:V=2ab+2bc+2ac, then I did: V-2bc=2ab+2ac.....I'm stuck.<BR>\n" );
document.write( "It would be great if I can see the steps and understand what I'm doing. Thanks!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327897 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V = 2*(ab + bc + ac)<BR>\n" );
document.write( "reorder the terms to get:<BR>\n" );
document.write( "V = 2*(ab + ac + bc)<BR>\n" );
document.write( "factor out the a to get:<BR>\n" );
document.write( "V = 2*(a(b+c) + bc)<BR>\n" );
document.write( "expand the equation to get:<BR>\n" );
document.write( "V = 2a(b+c)+2bc<BR>\n" );
document.write( "subtract 2bc from both sides of the equation to get:<BR>\n" );
document.write( "V-2bc = 2a(b+c)<BR>\n" );
document.write( "divide both sides by (b+c) to get:<BR>\n" );
document.write( "(V-2bc)/(b+x) = 2a<BR>\n" );
document.write( "divide both sides by 2 to get:<BR>\n" );
document.write( "(V-2bc)/(2(b+c)) = a<BR>\n" );
document.write( "commute to get:<BR>\n" );
document.write( "a = (V-2bc)/(2(b+c))<BR>\n" );
document.write( "assuming a = 1, b = 2, c = 3, your original equation gets:<BR>\n" );
document.write( "V = 2*(2+6+3) = 2*11 = 22<BR>\n" );
document.write( "plug the values for V and b and c into the final equation to get:<BR>\n" );
document.write( "(22-12)/(2(5)) = a which becomes:<BR>\n" );
document.write( "10/10 = 1 which is the value of a we started out with, so the conversion formula looks good.<BR>\n" );
document.write( "i think that's your answer.<BR>\n" );
document.write( "check it out for yourself to see if it works for you.<BR>\n" );
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