document.write( "Question 49006: 4m/m-3 + 6/3-m = m (Please help!) \n" ); document.write( "

Algebra.Com's Answer #32788 by Earlsdon(6294) $\"\"$ $\"About$

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Solve:
\n" ); document.write( " $\"4m%2F%28m-3%29+%2B+6%2F%283-m%29+=+m\"$ Rewrite the second term on the left side as: $\"-6%2F%28m-3%29\"$
\n" ); document.write( " $\"4m%2F%28m-3%29+-+6%2F%28m-3%29+=+m\"$ Add the fractions on the left side. The common denominator is (m-3).
\n" ); document.write( " $\"%284m-6%29%2F%28m-3%29+=+m\"$ Multiply both sides by (m-3).
\n" ); document.write( " $\"4m-6+=+m%28m-3%29\"$ Simplify this.
\n" ); document.write( " $\"4m-6+=+m%5E2-3m\"$ Subtract 4m from both sides.
\n" ); document.write( " $\"-6+=+m%5E2-7m\"$ Add 6 to both sides.
\n" ); document.write( " $\"m%5E2-7n%2B6+=+0\"$ Solve this quadratic equation by factoring.
\n" ); document.write( " $\"%28m-1%29%28m-6%29+=+0\"$ Apply the zero product principle.
\n" ); document.write( " $\"m-1+=+0\"$ and/or $\"m-6+=+0\"$
\n" ); document.write( "If $\"m-1+=+0\"$ then $\"m+=+1\"$
\n" ); document.write( "If $\"m-6+=+0\"$ them m $\"m+=+6\"$ \r
\n" ); document.write( "\n" ); document.write( "Solutions:
\n" ); document.write( "m = 1
\n" ); document.write( "m = 6\r
\n" ); document.write( "\n" ); document.write( "You can check the solutions by substituting them, one-at-a-time into the original equation. \n" ); document.write( "

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