document.write( "Question 478501: How to use the quadratic formula to solve for x if 3x(squared)+35=26x \n" ); document.write( "
Algebra.Com's Answer #327857 by cleomenius(959)\"\" \"About 
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First put in order.
\n" ); document.write( "3x^2 -26x + 35 = 0.\r
\n" ); document.write( "\n" ); document.write( "Next, assign a, b, and c.\r
\n" ); document.write( "\n" ); document.write( "a = 3
\n" ); document.write( "c = -26
\n" ); document.write( "c = 35\r
\n" ); document.write( "\n" ); document.write( "The formula is (-b +,- (sqrt( b^2 - 4ac))/ 2a \r
\n" ); document.write( "\n" ); document.write( "(26 +,- sqrt( (-26)^2 - 4(3)(35) ) / 2(3)\r
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\n" ); document.write( "\n" ); document.write( "(26 +,- sqrt(676 - 420) ) /6\r
\n" ); document.write( "\n" ); document.write( "(26 +,- sqrt ( 256)) / 6.
\n" ); document.write( "(26 + 16) /6 = 7
\n" ); document.write( "(26 - 16) /6 = 1.667\r
\n" ); document.write( "\n" ); document.write( "If you plug these into your original formulas, they will both check out.\r
\n" ); document.write( "\n" ); document.write( "Cleomenius.\r
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