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document.write( " find two consecutive even numbers if the sum of their squares is 100
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Algebra.Com's Answer #327836 by Theo(13342)![]() ![]() You can put this solution on YOUR website! an even number is one that is divisible by 2. \n" ); document.write( "let x be the first even number. \n" ); document.write( "let x + 2 be the second even number. \n" ); document.write( "the sum of their squares = 100 means: \n" ); document.write( "x^2 + (x+2)^2 = 100 \n" ); document.write( "expand this equation to get: \n" ); document.write( "x^2 + x^2 + 4x + 4 = 100 \n" ); document.write( "combine like terms to get: \n" ); document.write( "2x^2 + 4x + 4 = 100 \n" ); document.write( "divide both sides of the equation by 2 to get: \n" ); document.write( "x^2 + 2x + 2 = 50 \n" ); document.write( "subtract 100 from both sides of the equation to get: \n" ); document.write( "x^2 + 2x - 48 = 0 \n" ); document.write( "factor this quadratic equation to get: \n" ); document.write( "(x+8) * (x-6) = 0 \n" ); document.write( "solve for x to get: \n" ); document.write( "x = -8 or x = 6 \n" ); document.write( "if x = -8, then x+2 = -6 \n" ); document.write( "if x = 6, then x+2 = 8 \n" ); document.write( "in both cases, plugging those answers into he original equation will show that those values are good. \n" ); document.write( "when x = -8 and x+2 = -6, we get: \n" ); document.write( "64 + 36 = 100 \n" ); document.write( "when x = 6 and x+2 = 8, we get: \n" ); document.write( "36 + 64 = 100 \n" ); document.write( " \n" ); document.write( " |