document.write( "Question 478415: Solve each system graphically. Be sure to check your solution. If a system has an infinite number of solutions, use set builder notation to write the solution set. If a system has no solution, state this.\r
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document.write( "b+ 2a = 2,\r
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document.write( "a= -3 - b \n" );
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Algebra.Com's Answer #327822 by mananth(16946)![]() ![]() You can put this solution on YOUR website! b+ 2a = 2,\r \n" ); document.write( "\n" ); document.write( "a= -3 - b\r \n" ); document.write( "\n" ); document.write( "equation1 \n" ); document.write( "when a= 0 b= 2 ( 0 , 2 ) \n" ); document.write( "when b = 0 a= 1 ( 1 , 0 ) \n" ); document.write( "Equation 2 \n" ); document.write( "when a= 0 b= -3 ( 0 , -3 ) \n" ); document.write( "when b = 0 a= -3 ( -3 , 0 )\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From graph you find solution is (5,-8)\r \n" ); document.write( "\n" ); document.write( "2 a + 1 b = 2 .............1 \n" ); document.write( "1 a + 1 b = -3 .............2 \n" ); document.write( " \n" ); document.write( "multiply (1)by 1 \n" ); document.write( "Multiply (2) by -1 \n" ); document.write( "2 a + 1 b = 2 \n" ); document.write( "-1 a + -1 b = 3 \n" ); document.write( "Add the two equations \n" ); document.write( "1 a = 5 \n" ); document.write( "/ 1 \n" ); document.write( "a = 5 \n" ); document.write( "plug value of a in (1) \n" ); document.write( "2 a + 1 b = 2 \n" ); document.write( "10 + 1 b = 2 \n" ); document.write( " 1 b = 2 -10 \n" ); document.write( " 1 b = -8 \n" ); document.write( " b = -8.00 \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |