document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478450>Question 478450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a train travels 40 miles per hour from one city to another, it reaches 10 minutes late and if it travels 30 miles per hour then it reaches 16 minutes late. What is distance between two cities.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327807 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let t be the exact time it has to reach<BR>\n" );
document.write( "x/40 =t+1/6\r<BR>\n" );
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document.write( "x/40-1/6= t\r<BR>\n" );
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document.write( "x/30 =t+4/15<BR>\n" );
document.write( "x/30 -4/15=t\r<BR>\n" );
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document.write( "x/40-1/6 = x/30-4/15\r<BR>\n" );
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document.write( "x/40-x/30 = -4/15+1/6\r<BR>\n" );
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document.write( "(3x-4x)/120 = (-8+5)/30\r<BR>\n" );
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document.write( "-x= 4(-3)<BR>\n" );
document.write( "-x=-12<BR>\n" );
document.write( "x=12 miles\r<BR>\n" );
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