document.write( "Question 478444: the width of a rectangle is 2ft less than the length. The area is 3ft^2. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #327804 by Maths68(1474)\"\" \"About 
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Width=w
\n" ); document.write( "Length=l\r
\n" ); document.write( "\n" ); document.write( "w = l-2 ………….(1)\r
\n" ); document.write( "\n" ); document.write( "Area of rectangle (A) = 3 \r
\n" ); document.write( "\n" ); document.write( "A= l * w
\n" ); document.write( "Put the values of ‘w’ and ‘A’ in above equation.\r
\n" ); document.write( "\n" ); document.write( "3= l * (l – 2)
\n" ); document.write( "3=l^2-2l
\n" ); document.write( "l^2-2l-3=0
\n" ); document.write( "l^2-3l+l-3=0
\n" ); document.write( "l(l-3)+1(l-3)=0
\n" ); document.write( "(l+1)(l-3)=0
\n" ); document.write( "l+1=0 or l-3=0
\n" ); document.write( "l=-1 or l=3
\n" ); document.write( "Length cannot be negative
\n" ); document.write( "Therefore l=3 ft
\n" ); document.write( "Put the value of l in equation (1)
\n" ); document.write( "w = l-2
\n" ); document.write( "w =3-2
\n" ); document.write( "w=1 ft
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