document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478395>Question 478395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve for x: 2logx=log2+log(3x-4) thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327786 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2logx=log2+log(3x-4)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "2logx=log2+log(3x-4)<BR>\n" );
document.write( "2logx-log2-log(3x-4)=0<BR>\n" );
document.write( "2logx-(log2+log(3x-4))=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log (x^2/2*(3x-4))=0<BR>\n" );
document.write( "convert to exponential form: base(10) raised to log of number(0)=number(x^2/2*(3x-4))<BR>\n" );
document.write( "10^0=(x^2/2*(3x-4))<BR>\n" );
document.write( "1=x^2/6x-8<BR>\n" );
document.write( "x^2=6x-8<BR>\n" );
document.write( "x^2-6x+8=0<BR>\n" );
document.write( "(x-4)(x-2)=0<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x=2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );