document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49337>Question 49337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32776 by </B><A HREF=/tutors/aboutme.mpl?userid=mszlmb><B>mszlmb(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mszlmb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mszlmb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number\r<BR>\n" );
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document.write( "x is bigger, y is smaller<BR>\n" );
document.write( "x=12+y<BR>\n" );
document.write( "y+2x=39\r<BR>\n" );
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document.write( "take the first equation, x=12+y<BR>\n" );
document.write( "-12 on both sides: x-12=y\r<BR>\n" );
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document.write( "now replace y in the second equation with its equivalent, x-12<BR>\n" );
document.write( "x-12+2x=39   +12 both sides<BR>\n" );
document.write( "3x=51<BR>\n" );
document.write( "x=51/3=17.\r<BR>\n" );
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document.write( "X, the larger number, =17. </SPAN>\n" );
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