document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478338>Question 478338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the following without a calculator: log8 of the 4th root of 1/2\r<BR>\n" );
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document.write( "I believe that I should be doing the 4th root of 1/2 and taking it to the 8th power? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327748 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log8 means 1/2 as a power of 8\r<BR>\n" );
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document.write( "8^(1/3) = 2 ___ 2^(-1) = 1/2 ___ so ___ 8^(-1/3) = 1/2 ___ and ___ log8(1/2) = -1/3\r<BR>\n" );
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document.write( "log8[1/2^(1/4)] = (-1/3)(1/4) = -1/12 </SPAN>\n" );
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