document.write( "Question 478335: Can you please help with the following problem?\r
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document.write( "Find the vertex f(x) = -2x^2+2x+6\r
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document.write( "Can you please show the steps so that I can figure out where I am going wrong. Thank you \n" );
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Algebra.Com's Answer #327739 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex f(x) = -2x^2+2x+6 \n" ); document.write( "** \n" ); document.write( "Standard form of an equation for a parabola: A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness of the curve. \n" ); document.write( ".. \n" ); document.write( "f(x)=-2x^2+2x+6 \n" ); document.write( "completing the square to see equation in standard form \n" ); document.write( "f(x)=-2(x^2-x+1/4)+6+1/2 \n" ); document.write( "f(x)=-2(x-1/2)^2+13/2 \n" ); document.write( "This is an equation of a parabola with vertex at (1,13/2). The negative coefficient of the lead term means it opens downward, that is, it has a maximum. \n" ); document.write( "see the graph below as a visual check on the answer \n" ); document.write( ".. \n" ); document.write( " |