document.write( "Question 478335: Can you please help with the following problem?\r
\n" ); document.write( "\n" ); document.write( "Find the vertex f(x) = -2x^2+2x+6\r
\n" ); document.write( "\n" ); document.write( "Can you please show the steps so that I can figure out where I am going wrong. Thank you
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Algebra.Com's Answer #327739 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Find the vertex f(x) = -2x^2+2x+6
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\n" ); document.write( "Standard form of an equation for a parabola: A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness of the curve.
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\n" ); document.write( "f(x)=-2x^2+2x+6
\n" ); document.write( "completing the square to see equation in standard form
\n" ); document.write( "f(x)=-2(x^2-x+1/4)+6+1/2
\n" ); document.write( "f(x)=-2(x-1/2)^2+13/2
\n" ); document.write( "This is an equation of a parabola with vertex at (1,13/2). The negative coefficient of the lead term means it opens downward, that is, it has a maximum.
\n" ); document.write( "see the graph below as a visual check on the answer
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C-2x%5E2%2B2x%2B6%29+\"
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