document.write( "Question 478146: the length of rectangle B is 50% longer than the than the length of rectangle A and the width of rectangle B is 50% shorter than the width of rectangle A.what is the ratio between the area of rectangle B and the area of rectangle A?
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Algebra.Com's Answer #327735 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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the length of rectangle B is 50% longer than the than the length of rectangle A
\n" ); document.write( "and the width of rectangle B is 50% shorter than the width of rectangle A.
\n" ); document.write( "what is the ratio between the area of rectangle B and the area of rectangle A?
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\n" ); document.write( "Let L = Length of A
\n" ); document.write( "Let W = Width of A
\n" ); document.write( "then
\n" ); document.write( "LW = area of A
\n" ); document.write( "and
\n" ); document.write( "1.5L = Length of B
\n" ); document.write( ".5W = Width of B
\n" ); document.write( "then
\n" ); document.write( "1.5L*.5W = .75LW, the area of B
\n" ); document.write( ":
\n" ); document.write( "Ratio: $\"%28LW%29%2F%28.75LW%29\"$
\n" ); document.write( "Cancel LW, make it into integers
\n" ); document.write( " $\"1%2F.75\"$ * $\"4%2F4\"$ = $\"4%2F3\"$ is A to B Ratio
\n" ); document.write( "4:3 is the area of B to A
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