document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474699>Question 474699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ray SU bisects angle RST. The measure of angle RSU=3x-1, the measure of angle UST=2x+13 and the measure of angle RST=6x-2. Find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327708 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since SU bisects RST, angle RSU plus angle UST equals angle RST.\r<BR>\n" );
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document.write( "We are given RST = 6x -2<BR>\n" );
document.write( "We are given RSU = 3x -1<BR>\n" );
document.write( "We are given UST = 2x + 13\r<BR>\n" );
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document.write( "Therefore, 3x - 1 + 2x + 13 = 6x -2<BR>\n" );
document.write( "5x + 12  = 6x - 2<BR>\n" );
document.write( "14 = x\r<BR>\n" );
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document.write( "RST = 6(14)  - 2 = 82<BR>\n" );
document.write( "RSU = 3(14) - 1  = 41<BR>\n" );
document.write( "UST = 2x + 13   =  41\r<BR>\n" );
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document.write( "Therefore, this does check.\r<BR>\n" );
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document.write( "Cleomenius </SPAN>\n" );
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