document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478231>Question 478231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The flower garden has the shape of a right triangle.  17ft of a perennial border forms the hypotenuse of the triangle, and one leg is 7ft longer than the other leg.  Find the lengths of the legs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327669 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since this is a right triangle, we can use a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "Let one leg be x.<BR>\n" );
document.write( "Let the other leg be x + 7.\r<BR>\n" );
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document.write( "x^2  + (x + 7)^2  =  289<BR>\n" );
document.write( "x^2  + x^2  + 14x  + 49 = 289<BR>\n" );
document.write( "2x^2  + 14x  -  240  = 0<BR>\n" );
document.write( "2 ( x^2  + 7x - 120) = 0<BR>\n" );
document.write( "2 (x - 8) ( x + 15) = 0\r<BR>\n" );
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document.write( "x will = 8, one leg of the triangle.<BR>\n" );
document.write( "8 + 7 = 15, the other leg of the triangle.<BR>\n" );
document.write( "8^2   +    15^2   =   17^2<BR>\n" );
document.write( "64   +     225     =   289, The results do check.\r<BR>\n" );
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document.write( "Cleomenius.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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