document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=478167>Question 478167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "Can i get solution for this problem\r<BR>\n" );
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document.write( "a^(logb-logc)* b^(logc-loga)* C^(loga-logb)\r<BR>\n" );
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document.write( "Thanks and regards,<BR>\n" );
document.write( "AN </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #327629 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=327629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^(logb-logc)* b^(logc-loga)* C^(loga-logb)<BR>\n" );
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document.write( "We can remove the exponents by taking the log of the expression:<BR>\n" );
document.write( "log(a^(logb-logc)* b^(logc-loga)* C^(loga-logb)) = <BR>\n" );
document.write( "  log(a^(logb-logc)) + log(b^(logc-loga)) + log(c^(loga-logb))<BR>\n" );
document.write( "  = (logb-logc)loga + (logc-loga)logb + (loga-logb)logc<BR>\n" );
document.write( "  = logb*loga - loga*logc + logc*logb - loga*logb + loga*logc - logc*logb<BR>\n" );
document.write( "All terms cancel, so the epxression = 0.<BR>\n" );
document.write( "To get back the original expresion, we need to \"undo\" the log:<BR>\n" );
document.write( " a^(logb-logc)*b^(logc-loga)*c^(loga-logb) = 10^0 = 1<BR>\n" );
document.write( "Ans: 1 </SPAN>\n" );
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