document.write( "Question 478102: If
\n" ); document.write( "\"+log+%28%28a%2Bb%29%2F2%29+=++%28log+a+%2B+log++b%29+1%2F2+\"
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Algebra.Com's Answer #327601 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%28a%2Bb%29%2F2%29+=+%28loga+%2Blogb%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "==> \"log%28%28a%2Bb%29%2F2%29+=+log%28sqrt%28ab%29%29\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28a%2Bb%29%2F2+=+sqrt%28ab%29\", since log is 1-to-1\r
\n" ); document.write( "\n" ); document.write( "==> \"%28a%2Bb%29+=+2sqrt%28ab%29\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28a%2Bb%29%5E2+=+4ab\", after squaring both sides.\r
\n" ); document.write( "\n" ); document.write( "==> \"a%5E2+%2B+2ab+%2B+b%5E2+=+4ab\"\r
\n" ); document.write( "\n" ); document.write( "==> \"a%5E2+-+2ab+%2B+b%5E2+=+0\"\r
\n" ); document.write( "\n" ); document.write( "==> \"%28a-b%29%5E2+=+0\" ==> a - b = 0, or a = b.
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