document.write( "Question 478103: How many gallons of a 12% salt solution must be mixed with 6 gallons of a 20% salt solution to obtain 13% salt solution? \n" ); document.write( "
Algebra.Com's Answer #327593 by mananth(16946)\"\" \"About 
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percent percentage ---------------- quantity
\n" ); document.write( "Salt solution 12 ----------------x gallons
\n" ); document.write( "Salt solution 20 ----------------6-x gallons
\n" ); document.write( "Mixture 13.00% ---------------- 6
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\n" ); document.write( "12x+20(6-x)=13* 6
\n" ); document.write( "12x+120-20x=78
\n" ); document.write( "12x-20x =78-120
\n" ); document.write( "-8x=-42
\n" ); document.write( "/-8
\n" ); document.write( "x=5.25 gallons 12.00% Salt solution
\n" ); document.write( "0.75 gallons 20.00% Salt solution
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